What is the answer to (2-n-3n^2)/(3n-2)=n+2 ?

The answer to (2-n-3n^2)/(3n-2)=n+2 is n=-3/2

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(2-n-3n^2)/(3n-2)=n+2

\frac{2 - n - 3 n ^{2}}{3 n - 2} = n + 2

n = - \frac{3}{2}

Decimal

n = - 1.5

Solution steps

\frac{2 - n - 3 n ^{2}}{3 n - 2} = n + 2

Simplify

\frac{2 - n - 3 n ^{2}}{3 n - 2} : - n - 1

- n - 1 = n + 2

Move

1

to the right side

- n = n + 3

Move

n

to the left side

- 2 n = 3

Divide both sides by

- 2

n = - \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

n = \frac{2}{3}

Combine undefined points with solutions:

n = - \frac{3}{2}

\frac{1800 x + 1440}{x + 1} = 1760

\frac{1}{x} + x = 0

\frac{5}{2 x} + \frac{1}{4} = \frac{1}{3}

0.005 = \frac{0.5}{8 \cdot 50000 \cdot C}

\frac{- 1}{x ^{2}} = 0

What is the answer to (2-n-3n^2)/(3n-2)=n+2 ?
The answer to (2-n-3n^2)/(3n-2)=n+2 is n=-3/2
Solve for n: (2-n-3n^2)/(3n-2)=n+2
The solution is n=-3/2