What is the answer to (y^2+3y+2)/(y+1)=0 ?

The answer to (y^2+3y+2)/(y+1)=0 is y=-2

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(y^2+3y+2)/(y+1)=0

\frac{y ^{2} + 3 y + 2}{y + 1} = 0

y = - 2

Solution steps

\frac{y ^{2} + 3 y + 2}{y + 1} = 0

Simplify

\frac{y ^{2} + 3 y + 2}{y + 1} : y + 2

y + 2 = 0

Move

2

to the right side

y = - 2

Verify Solutions

Find undefined (singularity) points:

y = - 1

Combine undefined points with solutions:

y = - 2

1 + \frac{2}{x - 8} = \frac{x}{x ^{2} - 12 x + 32}

2 - \frac{4}{x ^{2} - 7 x} = - \frac{7}{x - 7}

\frac{10}{x + 6} = - \frac{5}{3}

\frac{4}{x - 7} = \frac{- 2 x}{x + 3}

\frac{4 x}{x ^{2} - 9} = \frac{8}{x - 3}

What is the answer to (y^2+3y+2)/(y+1)=0 ?
The answer to (y^2+3y+2)/(y+1)=0 is y=-2
Solve for y: (y^2+3y+2)/(y+1)=0
The solution is y=-2