What is the answer to 1-2/(1+x^2)=0 ?

The answer to 1-2/(1+x^2)=0 is x=1,x=-1

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1-2/(1+x^2)=0

1 - \frac{2}{1 + x ^{2}} = 0

x = 1, x = - 1

Solution steps

1 - \frac{2}{1 + x ^{2}} = 0

Multiply both sides by

1 + x^{2}

x^{2} - 1 = 0

Solve

x^{2} - 1 = 0 : x = 1, x = - 1

x = 1, x = - 1

\frac{300}{x} + 8 = x - 200

\frac{- 32}{x} = - 8

\frac{2}{x + 5} = \frac{x + 2}{3 x + 11}

\frac{6}{x + 1} - \frac{1}{4} = \frac{1}{3 x + 3}

\frac{1}{x - 5} + \frac{3}{8} = \frac{6}{7}