What is the answer to (x^2+3x-18}{6x}=\frac{2-3x)/3 ?

The answer to (x^2+3x-18}{6x}=\frac{2-3x)/3 is x=(1+sqrt(505))/(14),x=(1-sqrt(505))/(14)

Solve for x: (x^2+3x-18}{6x}=\frac{2-3x)/3

The solution is x=(1+sqrt(505))/(14),x=(1-sqrt(505))/(14)

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\frac{x ^{2} + 3 x - 18}{6 x} = \frac{2 - 3 x}{3}

x = \frac{1 + 505}{14}, x = \frac{1 - 505}{14}

Decimal

x = 1.67658 \dots, x = - 1.53372 \dots

Solution steps

\frac{x ^{2} + 3 x - 18}{6 x} = \frac{2 - 3 x}{3}

Cross multiply

(x^{2} + 3 x - 18) \cdot 3 = 6 x (2 - 3 x)

Solve

(x^{2} + 3 x - 18) \cdot 3 = 6 x (2 - 3 x) : x = \frac{1 + 505}{14}, x = \frac{1 - 505}{14}

x = \frac{1 + 505}{14}, x = \frac{1 - 505}{14}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1 + 505}{14}, x = \frac{1 - 505}{14}

t, y = \frac{t - a}{t + 3}

2 x - \frac{1}{x} - 1 = 0

y, \frac{3}{3 x + y} = 1

\frac{x - 1}{x} = \frac{x + 1}{x + 3}

\frac{1}{2 k} = \frac{1}{2} - \frac{5}{k}

What is the answer to (x^2+3x-18}{6x}=\frac{2-3x)/3 ?
The answer to (x^2+3x-18}{6x}=\frac{2-3x)/3 is x=(1+sqrt(505))/(14),x=(1-sqrt(505))/(14)
Solve for x: (x^2+3x-18}{6x}=\frac{2-3x)/3
The solution is x=(1+sqrt(505))/(14),x=(1-sqrt(505))/(14)