What is the answer to 4/(2x+1)+1/(4x^2-1)=3 ?

The answer to 4/(2x+1)+1/(4x^2-1)=3 is x= 2/3 ,x=0

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4/(2x+1)+1/(4x^2-1)=3

\frac{4}{2 x + 1} + \frac{1}{4 x ^{2} - 1} = 3

x = \frac{2}{3}, x = 0

Decimal

x = 0.66666 \dots, x = 0

Solution steps

\frac{4}{2 x + 1} + \frac{1}{4 x ^{2} - 1} = 3

Multiply by LCM

4 (2 x - 1) + 1 = 3 (2 x + 1) (2 x - 1)

Solve

4 (2 x - 1) + 1 = 3 (2 x + 1) (2 x - 1) : x = \frac{2}{3}, x = 0

x = \frac{2}{3}, x = 0

Verify Solutions

Find undefined (singularity) points:

x = - \frac{1}{2}, x = \frac{1}{2}

Combine undefined points with solutions:

x = \frac{2}{3}, x = 0

\frac{1}{x ^{2} - 8 x} + \frac{6 x}{x - 8} = - 1

\frac{1}{x} + \frac{1}{x + 5} = \frac{1}{6}

\frac{600}{300 + x} = \frac{400}{300 - x}

\frac{3}{4 ( 2 x - 3 )} = 1

1 - \frac{3}{x} = 0

What is the answer to 4/(2x+1)+1/(4x^2-1)=3 ?
The answer to 4/(2x+1)+1/(4x^2-1)=3 is x= 2/3 ,x=0
Solve for x: 4/(2x+1)+1/(4x^2-1)=3
The solution is x= 2/3 ,x=0