What is the answer to 6^{x-7}-8=40 ?

The answer to 6^{x-7}-8=40 is x=(ln(48))/(ln(6))+7

Solve for x: 6^{x-7}-8=40

The solution is x=(ln(48))/(ln(6))+7

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6^{x - 7} - 8 = 40

x = \frac{ln ( 48 )}{ln ( 6 )} + 7

Decimal

x = 9.16055 \dots

Solution steps

6^{x - 7} - 8 = 40

Move

8

to the right side

6^{x - 7} = 48

Apply exponent rules

(x - 7) ln (6) = ln (48)

Solve

(x - 7) ln (6) = ln (48) : x = \frac{ln ( 48 )}{ln ( 6 )} + 7

x = \frac{ln ( 48 )}{ln ( 6 )} + 7

1 1^{x + 6} = 3^{x}

4 x e^{x} = 2

2^{\frac{1}{2}} = 4 e^{- \frac{t}{0.00001}}

3^{20 - x} = 9

5 \times 2^{x + 1} = 15

What is the answer to 6^{x-7}-8=40 ?
The answer to 6^{x-7}-8=40 is x=(ln(48))/(ln(6))+7
Solve for x: 6^{x-7}-8=40
The solution is x=(ln(48))/(ln(6))+7