What is the answer to (3/5)^{x+1}= 25/9 ?

The answer to (3/5)^{x+1}= 25/9 is x=(ln(25/9))/(ln(3/5))-1

Solve for x: (3/5)^{x+1}= 25/9

The solution is x=(ln(25/9))/(ln(3/5))-1

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(\frac{3}{5})^{x + 1} = \frac{25}{9}

x = \frac{ln ( \frac{25}{9} )}{ln ( \frac{3}{5} )} - 1

Decimal

x = - 3

Solution steps

(\frac{3}{5})^{x + 1} = \frac{25}{9}

Apply exponent rules

(x + 1) ln (\frac{3}{5}) = ln (\frac{25}{9})

Solve

(x + 1) ln (\frac{3}{5}) = ln (\frac{25}{9}) : x = \frac{ln ( \frac{25}{9} )}{ln ( \frac{3}{5} )} - 1

x = \frac{ln ( \frac{25}{9} )}{ln ( \frac{3}{5} )} - 1

(\frac{1}{4})^{x - 2} = 16

7^{x - 1} - 2^{x} = 0

9^{x} - 4^{x} = 6^{x}

7 e^{10 x} = 12

4^{x} - 3 \times 2^{x + 1} + 8 = 0

What is the answer to (3/5)^{x+1}= 25/9 ?
The answer to (3/5)^{x+1}= 25/9 is x=(ln(25/9))/(ln(3/5))-1
Solve for x: (3/5)^{x+1}= 25/9
The solution is x=(ln(25/9))/(ln(3/5))-1