What is the answer to 125^{x-1}=25^{x+3} ?

The answer to 125^{x-1}=25^{x+3} is x=9

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125^{x-1}=25^{x+3}

12 5^{x - 1} = 2 5^{x + 3}

x = 9

Solution steps

12 5^{x - 1} = 2 5^{x + 3}

Apply exponent rules

3 (x - 1) = 2 (x + 3)

Solve

3 (x - 1) = 2 (x + 3) : x = 9

x = 9

2^{3 x - 1} = 0.125

e^{e^{2 x}} = 3

2^{x} = 44

3 \times 3^{x} - 2 \times 3^{- x} = 1

3^{x^{2} + 1} = \frac{1}{9}

What is the answer to 125^{x-1}=25^{x+3} ?
The answer to 125^{x-1}=25^{x+3} is x=9
Solve for x: 125^{x-1}=25^{x+3}
The solution is x=9