What is the answer to 2^{3x-3}=32^{2x+5} ?

The answer to 2^{3x-3}=32^{2x+5} is x=-4

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2^{3x-3}=32^{2x+5}

2^{3 x - 3} = 3 2^{2 x + 5}

x = - 4

Solution steps

2^{3 x - 3} = 3 2^{2 x + 5}

Apply exponent rules

3 x - 3 = 5 (2 x + 5)

Solve

3 x - 3 = 5 (2 x + 5) : x = - 4

x = - 4

x, 121 = 2^{x}

2 e^{3 x} = 7

2^{3 x} = 0. 5^{3 x + 2}

3^{3 x} \cdot 6^{x} = \frac{1}{2916}

5 \cdot 2^{x + 3} = \frac{5}{4}

What is the answer to 2^{3x-3}=32^{2x+5} ?
The answer to 2^{3x-3}=32^{2x+5} is x=-4
Solve for x: 2^{3x-3}=32^{2x+5}
The solution is x=-4