What is the answer to 8^x= 1/(sqrt(2)) ?

The answer to 8^x= 1/(sqrt(2)) is x=-1/6

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8^x= 1/(sqrt(2))

8^{x} = \frac{1}{2}

x = - \frac{1}{6}

Decimal

x = - 0.16666 \dots

Solution steps

8^{x} = \frac{1}{2}

Apply exponent rules

3 x = - \frac{1}{2}

Solve

3 x = - \frac{1}{2} : x = - \frac{1}{6}

x = - \frac{1}{6}

1 6^{x} + 4^{x} - 6 = 0

9^{x} = \frac{1}{3}

4^{a} = 64

3^{2 x} = 3^{- x}

\frac{1}{e ^{x}} = 27

What is the answer to 8^x= 1/(sqrt(2)) ?
The answer to 8^x= 1/(sqrt(2)) is x=-1/6
Solve for x: 8^x= 1/(sqrt(2))
The solution is x=-1/6