What is the answer to 11^{3x-2}=65 ?

The answer to 11^{3x-2}=65 is x=(ln(7865))/(3ln(11))

Solve for x: 11^{3x-2}=65

The solution is x=(ln(7865))/(3ln(11))

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1 1^{3 x - 2} = 65

x = \frac{ln ( 7865 )}{3 ln ( 11 )}

Decimal

x = 1.24695 \dots

Solution steps

1 1^{3 x - 2} = 65

Apply exponent rules

(3 x - 2) ln (11) = ln (65)

Solve

(3 x - 2) ln (11) = ln (65) : x = \frac{ln ( 7865 )}{3 ln ( 11 )}

x = \frac{ln ( 7865 )}{3 ln ( 11 )}

3^{x} - 3^{x - 1} - 7 \cdot 3^{x - 3} = 33

x, z = e^{x y}

2^{x - 1} - 2^{x + 3} + 2^{x} = - \frac{13}{8}

3^{x} = 3 \frac{1}{4}

3 e^{- x} x^{2} - e^{- x} x^{3} = 0

What is the answer to 11^{3x-2}=65 ?
The answer to 11^{3x-2}=65 is x=(ln(7865))/(3ln(11))
Solve for x: 11^{3x-2}=65
The solution is x=(ln(7865))/(3ln(11))