What is the answer to 10^{7-x}=5^{x+1} ?

The answer to 10^{7-x}=5^{x+1} is x=(ln(2000000))/(ln(50))

Solve for x: 10^{7-x}=5^{x+1}

The solution is x=(ln(2000000))/(ln(50))

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1 0^{7 - x} = 5^{x + 1}

x = \frac{ln ( 2000000 )}{ln ( 50 )}

Decimal

x = 3.70873 \dots

Solution steps

1 0^{7 - x} = 5^{x + 1}

Apply exponent rules

(7 - x) ln (10) = (x + 1) ln (5)

Solve

(7 - x) ln (10) = (x + 1) ln (5) : x = \frac{ln ( 2000000 )}{ln ( 50 )}

x = \frac{ln ( 2000000 )}{ln ( 50 )}

8 (3^{6 - x}) = 40

5^{3 x} = 4^{2 x + 5}

2^{x} + 8^{x} = 130

4^{- 2 x} = 7

2^{6 x} = 0.125

What is the answer to 10^{7-x}=5^{x+1} ?
The answer to 10^{7-x}=5^{x+1} is x=(ln(2000000))/(ln(50))
Solve for x: 10^{7-x}=5^{x+1}
The solution is x=(ln(2000000))/(ln(50))