What is the answer to 9^x= 1/(\sqrt[3]{3)} ?

The answer to 9^x= 1/(\sqrt[3]{3)} is x=-1/6

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9^x= 1/(\sqrt[3]{3)}

9^{x} = \frac{1}{3 3}

x = - \frac{1}{6}

Decimal

x = - 0.16666 \dots

Solution steps

9^{x} = \frac{1}{3 3}

Apply exponent rules

2 x = - \frac{1}{3}

Solve

2 x = - \frac{1}{3} : x = - \frac{1}{6}

x = - \frac{1}{6}

2^{x + 3} = 3^{x + 2}

- 2 e^{- 2 x} = 0

4 x^{2} e^{- x^{2}} - 2 e^{- x^{2}} = 0

\frac{1}{1 - e ^{x}} = 5

16 \cdot 1 0^{5 x} = 96

What is the answer to 9^x= 1/(\sqrt[3]{3)} ?
The answer to 9^x= 1/(\sqrt[3]{3)} is x=-1/6
Solve for x: 9^x= 1/(\sqrt[3]{3)}
The solution is x=-1/6