What is the answer to 27=3^{5x}9^{x^2} ?

The answer to 27=3^{5x}9^{x^2} is x= 1/2 ,x=-3

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27=3^{5x}9^{x^2}

27 = 3^{5 x} 9^{x^{2}}

x = \frac{1}{2}, x = - 3

Decimal

x = 0.5, x = - 3

Solution steps

27 = 3^{5 x} \cdot 9^{x^{2}}

Apply exponent rules

3 = 5 x + 2 x^{2}

Solve

3 = 5 x + 2 x^{2} : x = \frac{1}{2}, x = - 3

x = \frac{1}{2}, x = - 3

e^{x} e^{2} = \frac{e ^{4}}{e ^{x + 1}}

3^{x - 1} = \frac{1}{3}

8^{x} = 45

8^{x} = \frac{1}{128}

t, A = P (1 + \frac{r}{n})^{n t}

What is the answer to 27=3^{5x}9^{x^2} ?
The answer to 27=3^{5x}9^{x^2} is x= 1/2 ,x=-3
Solve for x: 27=3^{5x}9^{x^2}
The solution is x= 1/2 ,x=-3