What is the answer to 6^{x-1}=8^{2-x} ?

The answer to 6^{x-1}=8^{2-x} is x=(ln(384))/(ln(48))

Solve for x: 6^{x-1}=8^{2-x}

The solution is x=(ln(384))/(ln(48))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6^{x - 1} = 8^{2 - x}

x = \frac{ln ( 384 )}{ln ( 48 )}

Decimal

x = 1.53715 \dots

Solution steps

6^{x - 1} = 8^{2 - x}

Apply exponent rules

(x - 1) ln (6) = (2 - x) ln (8)

Solve

(x - 1) ln (6) = (2 - x) ln (8) : x = \frac{ln ( 384 )}{ln ( 48 )}

x = \frac{ln ( 384 )}{ln ( 48 )}

6^{3 x + 2} = 3 6^{x - 6}

2 (5^{x}) = 32

2^{2 x + 2} = 2^{3 x}

e^{2 x} - 12 e^{x} + 11 = 0

e^{x^{2}} = e^{3 x} \cdot \frac{1}{e ^{2}}

What is the answer to 6^{x-1}=8^{2-x} ?
The answer to 6^{x-1}=8^{2-x} is x=(ln(384))/(ln(48))
Solve for x: 6^{x-1}=8^{2-x}
The solution is x=(ln(384))/(ln(48))