What is the answer to 27^{x+5}=243^{x-1} ?

The answer to 27^{x+5}=243^{x-1} is x=10

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27^{x+5}=243^{x-1}

2 7^{x + 5} = 24 3^{x - 1}

x = 10

Solution steps

2 7^{x + 5} = 24 3^{x - 1}

Apply exponent rules

3 (x + 5) = 5 (x - 1)

Solve

3 (x + 5) = 5 (x - 1) : x = 10

x = 10

e^{- 4 x} - 4 e^{- 4 x} x = 0

5^{x - 4} = 3^{2 x}

3^{2 x} (3^{2 x - 1})^{3} = 9

e^{- x} x^{4} - 8 e^{- x} x^{3} + 12 e^{- x} x^{2} = 0

3^{x} = 5^{2 x}

What is the answer to 27^{x+5}=243^{x-1} ?
The answer to 27^{x+5}=243^{x-1} is x=10
Solve for x: 27^{x+5}=243^{x-1}
The solution is x=10