What is the answer to 2^{x-x^2}= 1/(4^x) ?

The answer to 2^{x-x^2}= 1/(4^x) is x=0,x=3

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2^{x-x^2}= 1/(4^x)

2^{x - x^{2}} = \frac{1}{4 ^{x}}

x = 0, x = 3

Solution steps

2^{x - x^{2}} = \frac{1}{4 ^{x}}

Apply exponent rules

x - x^{2} = - 2 x

Solve

x - x^{2} = - 2 x : x = 0, x = 3

x = 0, x = 3

Verify Solutions:

x = 0

True

, x = 3

True

The solutions are

x = 0, x = 3

62 5^{x} = \frac{1}{5}

e^{x^{2}} = 5 e^{2 x - 1}

2 5^{v - 2} = 625

2 5^{- 1} = 5^{2 x - 4}

e^{3 x} = e^{2 - x}

What is the answer to 2^{x-x^2}= 1/(4^x) ?
The answer to 2^{x-x^2}= 1/(4^x) is x=0,x=3
Solve for x: 2^{x-x^2}= 1/(4^x)
The solution is x=0,x=3