What is the answer to 40-23=327e^{-9.22\times 10^{-4}t} ?

The answer to 40-23=327e^{-9.22\times 10^{-4}t} is t=-(10000ln(17/327))/(9.22)

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40-23=327e^{-9.22\times 10^{-4}t}

40 - 23 = 327 e^{- 9.22 \cdot 1 0^{- 4} t}

t = - \frac{10000 ln ( \frac{17}{327} )}{9.22}

Decimal

t = 3206.88376 \dots

Solution steps

40 - 23 = 327 e^{- 9.22 \cdot 1 0^{- 4} t}

Switch sides

327 e^{- 9.22 \cdot 1 0^{- 4} t} = 40 - 23

Subtract the numbers:

40 - 23 = 17

327 e^{- 9.22 \cdot 1 0^{- 4} t} = 17

Divide both sides by

327

e^{- 9.22 \cdot 1 0^{- 4} t} = \frac{17}{327}

Apply exponent rules

- 9.22 \cdot 1 0^{- 4} t = ln (\frac{17}{327})

Solve

- 9.22 \cdot 1 0^{- 4} t = ln (\frac{17}{327}) : t = - \frac{10000 ln ( \frac{17}{327} )}{9.22}

t = - \frac{10000 ln ( \frac{17}{327} )}{9.22}

0. 3^{3 x - 2} = 1

2^{l o g_{8} (5 x - 3)} = 4

5^{x - 2} = 11.18

- 8 e^{- x} = 0

2^{3 x - 2} = 1 6^{x + 4}

What is the answer to 40-23=327e^{-9.22\times 10^{-4}t} ?
The answer to 40-23=327e^{-9.22\times 10^{-4}t} is t=-(10000ln(17/327))/(9.22)