What is the answer to 8^{x-1}= 1/(16sqrt(2)) ?

The answer to 8^{x-1}= 1/(16sqrt(2)) is x=-1/2

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8^{x-1}= 1/(16sqrt(2))

8^{x - 1} = \frac{1}{16 2}

x = - \frac{1}{2}

Decimal

x = - 0.5

Solution steps

8^{x - 1} = \frac{1}{16 2}

Apply exponent rules

3 (x - 1) = - \frac{9}{2}

Solve

3 (x - 1) = - \frac{9}{2} : x = - \frac{1}{2}

x = - \frac{1}{2}

\frac{32}{8 16} = 2^{x}

2^{x + 3} - 2^{x + 1} = 12

2 e^{4 x - 6} = 16

5^{12 - x} = \frac{1}{125}

2^{2 x} = 2^{6} + 8^{2}

What is the answer to 8^{x-1}= 1/(16sqrt(2)) ?
The answer to 8^{x-1}= 1/(16sqrt(2)) is x=-1/2
Solve for x: 8^{x-1}= 1/(16sqrt(2))
The solution is x=-1/2