What is the answer to \sqrt[x]{27}=3^{x+2} ?

The answer to \sqrt[x]{27}=3^{x+2} is x=1,x=-3

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\sqrt[x]{27}=3^{x+2}

x 27 = 3^{x + 2}

x = 1, x = - 3

Solution steps

x 27 = 3^{x + 2}

Apply exponent rules

\frac{3}{x} = x + 2

Solve

\frac{3}{x} = x + 2 : x = 1, x = - 3

x = 1, x = - 3

y, x = \frac{e ^{y} - e ^{- y}}{2}

6^{x + 2} + 6^{x} = 222

e^{3 x + 2} = 9

2^{4 x + 2} - 48 \cdot 2^{2 x - 2} + 8 = 0

3 e^{2 x - 3} - 4 = 78

What is the answer to \sqrt[x]{27}=3^{x+2} ?
The answer to \sqrt[x]{27}=3^{x+2} is x=1,x=-3
Solve for x: \sqrt[x]{27}=3^{x+2}
The solution is x=1,x=-3