What is the answer to 2^{x+3}=5^{3x-1} ?

The answer to 2^{x+3}=5^{3x-1} is x=(ln(40))/(3ln(5)-ln(2))

Solve for x: 2^{x+3}=5^{3x-1}

The solution is x=(ln(40))/(3ln(5)-ln(2))

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2^{x + 3} = 5^{3 x - 1}

x = \frac{ln ( 40 )}{3 ln ( 5 ) - ln ( 2 )}

Decimal

x = 0.89207 \dots

Solution steps

2^{x + 3} = 5^{3 x - 1}

Apply exponent rules

(x + 3) ln (2) = (3 x - 1) ln (5)

Solve

(x + 3) ln (2) = (3 x - 1) ln (5) : x = \frac{ln ( 40 )}{3 ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 40 )}{3 ln ( 5 ) - ln ( 2 )}

5^{x} = 12 5^{x + 1}

y, x = 1 - e^{- λ \cdot y}

5700 = 3 e^{0.8 x} + 1

2 \cdot 3^{1 - x} + 3^{x - 1} = 3^{x}

84 \cdot 2^{x} = 420

What is the answer to 2^{x+3}=5^{3x-1} ?
The answer to 2^{x+3}=5^{3x-1} is x=(ln(40))/(3ln(5)-ln(2))
Solve for x: 2^{x+3}=5^{3x-1}
The solution is x=(ln(40))/(3ln(5)-ln(2))