What is the answer to 3^x+3^{x+4}+3^{x-1}= 247/27 ?

The answer to 3^x+3^{x+4}+3^{x-1}= 247/27 is x=-2

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3^x+3^{x+4}+3^{x-1}= 247/27

3^{x} + 3^{x + 4} + 3^{x - 1} = \frac{247}{27}

x = - 2

Solution steps

3^{x} + 3^{x + 4} + 3^{x - 1} = \frac{247}{27}

Factor

3^{x} + 3^{x + 4} + 3^{x - 1} : 247 \cdot 3^{x - 1}

247 \cdot 3^{x - 1} = \frac{247}{27}

Divide both sides by

247

3^{x - 1} = \frac{1}{27}

Apply exponent rules

x - 1 = - 3

Solve

x - 1 = - 3 : x = - 2

x = - 2

3^{5 x} = 2 7^{2 x - 4}

2^{x + 3} = 16

\frac{75}{1 + 15 e ^{- 0.4 x}} = 25

7^{x^{2}} = (\frac{1}{49})^{3 x + 4}

5^{1 - 2 x} = 3^{x + 3}

What is the answer to 3^x+3^{x+4}+3^{x-1}= 247/27 ?
The answer to 3^x+3^{x+4}+3^{x-1}= 247/27 is x=-2
Solve for x: 3^x+3^{x+4}+3^{x-1}= 247/27
The solution is x=-2