What is the answer to 7^x=64 ?

The answer to 7^x=64 is x=(6ln(2))/(ln(7))

The solution is x=(6ln(2))/(ln(7))

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7^x=64

7^{x} = 64

x = \frac{6 ln ( 2 )}{ln ( 7 )}

Decimal

x = 2.13724 \dots

Solution steps

7^{x} = 64

Apply exponent rules

x ln (7) = ln (64)

Solve

x ln (7) = ln (64) : x = \frac{6 ln ( 2 )}{ln ( 7 )}

x = \frac{6 ln ( 2 )}{ln ( 7 )}

\frac{e ^{y} - 1}{2 - 3 e ^{y}} = \frac{2}{7}

4^{x + 1} = 25 6^{1}

a^{2 x}

4^{x} = 8^{5 - x}

3 2^{x - 3} = 1 6^{x - 5}