What is the answer to 4^{X+1}-3*2^{X+1}=0 ?

The answer to 4^{X+1}-3*2^{X+1}=0 is X=(ln(3)-ln(2))/(ln(2))

Solve for X: 4^{X+1}-3*2^{X+1}=0

The solution is X=(ln(3)-ln(2))/(ln(2))

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4^{X + 1} - 3 \cdot 2^{X + 1} = 0

X = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 )}

Decimal

X = 0.58496 \dots

Solution steps

4^{X + 1} - 3 \cdot 2^{X + 1} = 0

Add

3 \cdot 2^{X + 1}

to both sides

4^{X + 1} - 3 \cdot 2^{X + 1} + 3 \cdot 2^{X + 1} = 0 + 3 \cdot 2^{X + 1}

Simplify

4^{X + 1} = 3 \cdot 2^{X + 1}

Apply exponent rules

2 (X + 1) ln (2) = ln (3) + (X + 1) ln (2)

Solve

2 (X + 1) ln (2) = ln (3) + (X + 1) ln (2) : X = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 )}

X = \frac{ln ( 3 ) - ln ( 2 )}{ln ( 2 )}

4^{x} + 5 \times 2^{2 x} = 2462

e^{2 x} - 2 e^{x} = 8

1 6^{x - 3} = 3^{- 5 x}

10 e^{8 x - 3} + 2 = 8 e^{8 x}

4^{3 x} = 8^{x} + 3

What is the answer to 4^{X+1}-3*2^{X+1}=0 ?
The answer to 4^{X+1}-3*2^{X+1}=0 is X=(ln(3)-ln(2))/(ln(2))
Solve for X: 4^{X+1}-3*2^{X+1}=0
The solution is X=(ln(3)-ln(2))/(ln(2))