What is the answer to 5+7*9^{2r+7}=20 ?

The answer to 5+7*9^{2r+7}=20 is r=(ln(5/11160261))/(4ln(3))

Solve for r: 5+7*9^{2r+7}=20

The solution is r=(ln(5/11160261))/(4ln(3))

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5 + 7 \cdot 9^{2 r + 7} = 20

r = \frac{ln ( \frac{5}{11160261} )}{4 ln ( 3 )}

Decimal

r = - 3.32656 \dots

Solution steps

5 + 7 \cdot 9^{2 r + 7} = 20

Move

5

to the right side

7 \cdot 9^{2 r + 7} = 15

Divide both sides by

7

9^{2 r + 7} = \frac{15}{7}

Apply exponent rules

(2 r + 7) ln (9) = ln (\frac{15}{7})

Solve

(2 r + 7) ln (9) = ln (\frac{15}{7}) : r = \frac{ln ( \frac{5}{11160261} )}{4 ln ( 3 )}

r = \frac{ln ( \frac{5}{11160261} )}{4 ln ( 3 )}

6^{2 x + 5} = 21 6^{x - 4}

1 0^{x} = 42

1 0^{x} = 49

(\frac{1}{2})^{x^{2}} = 3^{x}

1 6^{x^{2} + 1} = 2^{4 x + 7}

What is the answer to 5+7*9^{2r+7}=20 ?
The answer to 5+7*9^{2r+7}=20 is r=(ln(5/11160261))/(4ln(3))
Solve for r: 5+7*9^{2r+7}=20
The solution is r=(ln(5/11160261))/(4ln(3))