What is the answer to 32^{x-5}=8^{2x+3} ?

The answer to 32^{x-5}=8^{2x+3} is x=-34

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32^{x-5}=8^{2x+3}

3 2^{x - 5} = 8^{2 x + 3}

x = - 34

Solution steps

3 2^{x - 5} = 8^{2 x + 3}

Apply exponent rules

5 (x - 5) = 3 (2 x + 3)

Solve

5 (x - 5) = 3 (2 x + 3) : x = - 34

x = - 34

5^{1 - x} = 25

e^{2 x} + e^{- x} = 0

e^{x} - 1 - \frac{6}{e ^{x}} = 0

\frac{5 \cdot 2 ^{3 x - 1}}{4 ^{2 x - 1}} = 80

35 e^{- 0.001 x} = 95

What is the answer to 32^{x-5}=8^{2x+3} ?
The answer to 32^{x-5}=8^{2x+3} is x=-34
Solve for x: 32^{x-5}=8^{2x+3}
The solution is x=-34