What is the answer to 7^x=6^{x+7} ?

The answer to 7^x=6^{x+7} is x=(7ln(6))/(ln(7)-ln(6))

Solve for x: 7^x=6^{x+7}

The solution is x=(7ln(6))/(ln(7)-ln(6))

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7^{x} = 6^{x + 7}

x = \frac{7 ln ( 6 )}{ln ( 7 ) - ln ( 6 )}

Decimal

x = 81.36400 \dots

Solution steps

7^{x} = 6^{x + 7}

Apply exponent rules

x ln (7) = (x + 7) ln (6)

Solve

x ln (7) = (x + 7) ln (6) : x = \frac{7 ln ( 6 )}{ln ( 7 ) - ln ( 6 )}

x = \frac{7 ln ( 6 )}{ln ( 7 ) - ln ( 6 )}

7^{2 + x} = \frac{1}{4 9 ^{x + 3}}

3^{x} = 53

3^{x} = 38

1 6^{3 x} = 8^{x + 6}

(\frac{4}{9})^{x} = \frac{81}{16}

What is the answer to 7^x=6^{x+7} ?
The answer to 7^x=6^{x+7} is x=(7ln(6))/(ln(7)-ln(6))
Solve for x: 7^x=6^{x+7}
The solution is x=(7ln(6))/(ln(7)-ln(6))