What is the answer to 5^{1-x}=2^x ?

The answer to 5^{1-x}=2^x is x=(ln(5))/(ln(10))

Solve for x: 5^{1-x}=2^x

The solution is x=(ln(5))/(ln(10))

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5^{1 - x} = 2^{x}

x = \frac{ln ( 5 )}{ln ( 10 )}

Decimal

x = 0.69897 \dots

Solution steps

5^{1 - x} = 2^{x}

Apply exponent rules

(1 - x) ln (5) = x ln (2)

Solve

(1 - x) ln (5) = x ln (2) : x = \frac{ln ( 5 )}{ln ( 10 )}

x = \frac{ln ( 5 )}{ln ( 10 )}

3 6^{3} = 6^{x - 1}

x, \frac{J}{e} = J e^{- x y}

7^{x} + 7^{1 - x} = 8

3^{2 x + 1} = 4^{x - 1}

25 6^{x} = 128

What is the answer to 5^{1-x}=2^x ?
The answer to 5^{1-x}=2^x is x=(ln(5))/(ln(10))
Solve for x: 5^{1-x}=2^x
The solution is x=(ln(5))/(ln(10))