What is the answer to 10^{2x+1}=115 ?

The answer to 10^{2x+1}=115 is x=(ln(23/2))/(2ln(10))

Solve for x: 10^{2x+1}=115

The solution is x=(ln(23/2))/(2ln(10))

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1 0^{2 x + 1} = 115

x = \frac{ln ( \frac{23}{2} )}{2 ln ( 10 )}

Decimal

x = 0.53034 \dots

Solution steps

1 0^{2 x + 1} = 115

Apply exponent rules

(2 x + 1) ln (10) = ln (115)

Solve

(2 x + 1) ln (10) = ln (115) : x = \frac{ln ( \frac{23}{2} )}{2 ln ( 10 )}

x = \frac{ln ( \frac{23}{2} )}{2 ln ( 10 )}

100 = 75 e^{0.05 x}

1 4^{6 x} = 6 4^{x + 3}

[(4)^{2}]^{x} = 256

4^{- 2 x} \times 4^{x} = 64

6^{2 x} + 6^{x} - 56 = 0

What is the answer to 10^{2x+1}=115 ?
The answer to 10^{2x+1}=115 is x=(ln(23/2))/(2ln(10))
Solve for x: 10^{2x+1}=115
The solution is x=(ln(23/2))/(2ln(10))