What is the answer to solvefor y,9^{x+3}-27^{2y}=-3535662 ?

The answer to solvefor y,9^{x+3}-27^{2y}=-3535662 is y=(ln(3535662+3^{2(x+3)}))/(6ln(3))

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solvefor y,9^{x+3}-27^{2y}=-3535662

solve for

y, 9^{x + 3} - 2 7^{2 y} = - 3535662

y = \frac{ln ( 3535662 + 3 ^{2 (x + 3)} )}{6 ln ( 3 )}

Solution steps

9^{x + 3} - 2 7^{2 y} = - 3535662

Move

9^{x + 3}

to the right side

- 2 7^{2 y} = - 3535662 - 9^{x + 3}

Divide both sides by

- 1

2 7^{2 y} = 3535662 + 9^{x + 3}

Apply exponent rules

3 \cdot 2 y ln (3) = ln (3535662 + 3^{2 (x + 3)})

Solve

3 \cdot 2 y ln (3) = ln (3535662 + 3^{2 (x + 3)}) : y = \frac{ln ( 3535662 + 3 ^{2 (x + 3)} )}{6 ln ( 3 )}

y = \frac{ln ( 3535662 + 3 ^{2 (x + 3)} )}{6 ln ( 3 )}

e^{x} = 1 + x

(2^{2})^{n} = 16

8^{6 y + 4} = 64

3^{x} + 3^{x + 3} = 756

5 e^{x} = 0

What is the answer to solvefor y,9^{x+3}-27^{2y}=-3535662 ?
The answer to solvefor y,9^{x+3}-27^{2y}=-3535662 is y=(ln(3535662+3^{2(x+3)}))/(6ln(3))