What is the answer to 64^{2x}=16^{x+1} ?

The answer to 64^{2x}=16^{x+1} is x= 1/2

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64^{2x}=16^{x+1}

6 4^{2 x} = 1 6^{x + 1}

x = \frac{1}{2}

Decimal

x = 0.5

Solution steps

6 4^{2 x} = 1 6^{x + 1}

Apply exponent rules

6 x = 2 (x + 1)

Solve

6 x = 2 (x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

x \times e^{x} = 0

lo g_{2} (4^{x + 4}) = - 2

x^{l o g_{10} (x)} = 10

2 e^{2 x} + e^{x} = 6

e^{x + 3} = 5

What is the answer to 64^{2x}=16^{x+1} ?
The answer to 64^{2x}=16^{x+1} is x= 1/2
Solve for x: 64^{2x}=16^{x+1}
The solution is x= 1/2