What is the answer to 4^{sqrt(x+1)}=64*2^{sqrt(x+1)} ?

The answer to 4^{sqrt(x+1)}=64*2^{sqrt(x+1)} is x=35

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4^{sqrt(x+1)}=64*2^{sqrt(x+1)}

4^{x + 1} = 64 \cdot 2^{x + 1}

x = 35

Solution steps

4^{x + 1} = 64 \cdot 2^{x + 1}

Apply exponent rules

2 x + 1 = x + 1 + 6

Solve

2 x + 1 = x + 1 + 6 : x = 35

x = 35

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\frac{3 ^{2 x + 5}}{9} = 3^{x + 1}

1 7^{X + 8} = 1 7^{10}

26214 4^{4 x + 6} = 409 6^{- x - 15}

16 = 1 0^{2 + 3 x}

What is the answer to 4^{sqrt(x+1)}=64*2^{sqrt(x+1)} ?
The answer to 4^{sqrt(x+1)}=64*2^{sqrt(x+1)} is x=35
Solve for x: 4^{sqrt(x+1)}=64*2^{sqrt(x+1)}
The solution is x=35