What is the answer to 3^{2x-4}=3^{5x+8} ?

The answer to 3^{2x-4}=3^{5x+8} is x=-4

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3^{2x-4}=3^{5x+8}

3^{2 x - 4} = 3^{5 x + 8}

x = - 4

Solution steps

3^{2 x - 4} = 3^{5 x + 8}

Apply exponent rules

2 x - 4 = 5 x + 8

Solve

2 x - 4 = 5 x + 8 : x = - 4

x = - 4

y, x = 1 2^{1 - 0.1 y}

9 9^{x + 9} = 999 9^{x + 9}

9 \cdot 2^{2 x} = 1

3 \frac{2 ^{7} - 2 ^{x}}{2 ^{x} - 2} = 2

1 = e^{t}

What is the answer to 3^{2x-4}=3^{5x+8} ?
The answer to 3^{2x-4}=3^{5x+8} is x=-4
Solve for x: 3^{2x-4}=3^{5x+8}
The solution is x=-4