What is the answer to 81^{x+2}=27^{5x+4} ?

The answer to 81^{x+2}=27^{5x+4} is x=-4/11

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81^{x+2}=27^{5x+4}

8 1^{x + 2} = 2 7^{5 x + 4}

x = - \frac{4}{11}

Decimal

x = - 0.36363 \dots

Solution steps

8 1^{x + 2} = 2 7^{5 x + 4}

Apply exponent rules

4 (x + 2) = 3 (5 x + 4)

Solve

4 (x + 2) = 3 (5 x + 4) : x = - \frac{4}{11}

x = - \frac{4}{11}

4^{x - 15} = \frac{1}{2}

x, 2^{x} = 16

3^{2 x} + 3^{x + 1} - 54 = 0

8^{x} = 70

5^{x - 6} = \frac{1}{25}

What is the answer to 81^{x+2}=27^{5x+4} ?
The answer to 81^{x+2}=27^{5x+4} is x=-4/11
Solve for x: 81^{x+2}=27^{5x+4}
The solution is x=-4/11