What is the answer to 125^{3x+7}=25^{5x-11} ?

The answer to 125^{3x+7}=25^{5x-11} is x=43

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125^{3x+7}=25^{5x-11}

12 5^{3 x + 7} = 2 5^{5 x - 11}

x = 43

Solution steps

12 5^{3 x + 7} = 2 5^{5 x - 11}

Apply exponent rules

3 (3 x + 7) = 2 (5 x - 11)

Solve

3 (3 x + 7) = 2 (5 x - 11) : x = 43

x = 43

3^{2 x} = \frac{1}{9}

2 \cdot 3^{x} + 5 \cdot 3^{x} - 3^{x} = 6

e^{x^{2} - 8} = e^{2 x}

64 e^{8 x} x^{2} + 32 e^{8 x} x + 2 e^{8 x} = 0

2^{(7 - 3 x)} = \frac{1}{4}

What is the answer to 125^{3x+7}=25^{5x-11} ?
The answer to 125^{3x+7}=25^{5x-11} is x=43
Solve for x: 125^{3x+7}=25^{5x-11}
The solution is x=43