What is the answer to 3*4^x+4*2^x+8=0 ?

The answer to 3*4^x+4*2^x+8=0 is No Solution for x\in\mathbb{R}

Solve for x: 3*4^x+4*2^x+8=0

The solution is No Solution for x\in\mathbb{R}

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3 \cdot 4^{x} + 4 \cdot 2^{x} + 8 = 0

No Solution for x \in R

Solution steps

3 \cdot 4^{x} + 4 \cdot 2^{x} + 8 = 0

Apply exponent rules

3 (2^{x})^{2} + 4 \cdot 2^{x} + 8 = 0

Rewrite the equation with

2^{x} = u

3 (u)^{2} + 4 u + 8 = 0

Solve

3 u^{2} + 4 u + 8 = 0 :

No Solution for

u \in R

No Solution for x \in R

3^{x} = x^{4}

x, 0 = 2 e^{- x} x + (- e^{- x}) x^{2}

4^{x} = 5^{x - 1}

y, x = 1 0^{y}

2^{x} = 134217728

What is the answer to 3*4^x+4*2^x+8=0 ?
The answer to 3*4^x+4*2^x+8=0 is No Solution for x\in\mathbb{R}
Solve for x: 3*4^x+4*2^x+8=0
The solution is No Solution for x\in\mathbb{R}