What is the answer to 125^{x+1}= 1/(\sqrt[3]{625)} ?

The answer to 125^{x+1}= 1/(\sqrt[3]{625)} is x=-13/9

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125^{x+1}= 1/(\sqrt[3]{625)}

12 5^{x + 1} = \frac{1}{3 625}

x = - \frac{13}{9}

Decimal

x = - 1.44444 \dots

Solution steps

12 5^{x + 1} = \frac{1}{3 625}

Apply exponent rules

3 (x + 1) = - \frac{4}{3}

Solve

3 (x + 1) = - \frac{4}{3} : x = - \frac{13}{9}

x = - \frac{13}{9}

8 1^{1 - 3 x} = 27

3^{x - 5} - 2 = 79

2 7^{2 x} = 24 3^{x - 2}

250000 = 50 e^{1.827226683 t}

5^{x + 1} = 4^{2 x - 3}

What is the answer to 125^{x+1}= 1/(\sqrt[3]{625)} ?
The answer to 125^{x+1}= 1/(\sqrt[3]{625)} is x=-13/9
Solve for x: 125^{x+1}= 1/(\sqrt[3]{625)}
The solution is x=-13/9