What is the answer to -9=-10+28(19/28)^x ?

The answer to -9=-10+28(19/28)^x is x=-(ln(28))/(ln(19/28))

Solve for x: -9=-10+28(19/28)^x

The solution is x=-(ln(28))/(ln(19/28))

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- 9 = - 10 + 28 (\frac{19}{28})^{x}

x = - \frac{ln ( 28 )}{ln ( \frac{19}{28} )}

Decimal

x = 8.59334 \dots

Solution steps

- 9 = - 10 + 28 (\frac{19}{28})^{x}

Switch sides

- 10 + 28 (\frac{19}{28})^{x} = - 9

Move

10

to the right side

28 (\frac{19}{28})^{x} = 1

Divide both sides by

28

(\frac{19}{28})^{x} = \frac{1}{28}

Apply exponent rules

x ln (\frac{19}{28}) = ln (\frac{1}{28})

Solve

x ln (\frac{19}{28}) = ln (\frac{1}{28}) : x = - \frac{ln ( 28 )}{ln ( \frac{19}{28} )}

x = - \frac{ln ( 28 )}{ln ( \frac{19}{28} )}

3^{2 x} - 3 (3^{x}) = 4

3^{x + 1} = 9^{x - 2}

\frac{A}{1 + B e ^{\frac{t}{2}}} = C

lo g_{2} (2^{x}) = x

2 e^{- x^{2}} = 0

What is the answer to -9=-10+28(19/28)^x ?
The answer to -9=-10+28(19/28)^x is x=-(ln(28))/(ln(19/28))
Solve for x: -9=-10+28(19/28)^x
The solution is x=-(ln(28))/(ln(19/28))