What are the solutions to the equation 4r^3+5r^2=0 ?

The solutions to the equation 4r^3+5r^2=0 are r=0,r=-5/4

Find the zeros of 4r^3+5r^2=0

The zeros of 4r^3+5r^2=0 are r=0,r=-5/4

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4 r^{3} + 5 r^{2} = 0

r = 0, r = - \frac{5}{4}

Decimal

r = 0, r = - 1.25

Solution steps

4 r^{3} + 5 r^{2} = 0

Factor

4 r^{3} + 5 r^{2} : r^{2} (4 r + 5)

r^{2} (4 r + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r = 0 or 4 r + 5 = 0

Solve

4 r + 5 = 0 : r = - \frac{5}{4}

The solutions are

r = 0, r = - \frac{5}{4}

x^{5} + 2 x^{3} + x = 0

x^{3} + 7 x^{2} - 9 x - 63 = 0

125 t^{10} - 2 t^{7} = 0

x^{4} = (4 x - 5)^{2}

- 3 (2 x + 1)^{3} = - 192

What are the solutions to the equation 4r^3+5r^2=0 ?
The solutions to the equation 4r^3+5r^2=0 are r=0,r=-5/4
Find the zeros of 4r^3+5r^2=0
The zeros of 4r^3+5r^2=0 are r=0,r=-5/4