What are the solutions to the equation roots x^3+6x^2+11x+6 ?

The solutions to the equation roots x^3+6x^2+11x+6 are x=-1,x=-2,x=-3

Find the zeros of roots x^3+6x^2+11x+6

The zeros of roots x^3+6x^2+11x+6 are x=-1,x=-2,x=-3

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roots

x^{3} + 6 x^{2} + 11 x + 6

x = - 1, x = - 2, x = - 3

Solution steps

x^{3} + 6 x^{2} + 11 x + 6

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 6 x^{2} + 11 x + 6 = 0

Factor

x^{3} + 6 x^{2} + 11 x + 6 : (x + 1) (x + 2) (x + 3)

(x + 1) (x + 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

The solutions are

x = - 1, x = - 2, x = - 3

x^{3} + 5 x^{2} - 8 x - 48 = 0

x^{3} - 8 x^{2} + 4 x + 48 = 0

x^{3} - 34 x - 12 = 0

x^{3} - x^{2} + 4 = 0

x^{5} - 3 x^{4} + 3 x^{3} - 3 x^{2} + 2 x = 0

What are the solutions to the equation roots x^3+6x^2+11x+6 ?
The solutions to the equation roots x^3+6x^2+11x+6 are x=-1,x=-2,x=-3
Find the zeros of roots x^3+6x^2+11x+6
The zeros of roots x^3+6x^2+11x+6 are x=-1,x=-2,x=-3