What are the solutions to the equation roots x^4-8x^2+16 ?

The solutions to the equation roots x^4-8x^2+16 are x=2,x=-2

Find the zeros of roots x^4-8x^2+16

The zeros of roots x^4-8x^2+16 are x=2,x=-2

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roots

x^{4} - 8 x^{2} + 16

x = 2, x = - 2

Solution steps

x^{4} - 8 x^{2} + 16

The roots are the intercepts with the x-axis

(y = 0)

x^{4} - 8 x^{2} + 16 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 8 u + 16 = 0

Solve

u^{2} - 8 u + 16 = 0 : u = 4

u = 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 4 : x = 2, x = - 2

The solutions are

x = 2, x = - 2

x^{4} - 2 x^{3} - 5 x^{2} + 10 x - 1

x^{3} + x^{2} + 9 x + 9 = 0

z^{4} = - 1 + i

(x^{2} - 10)^{2} - 3 (x^{2} - 10) - 4 = 0

2 x^{5} + 24 x = 14 x^{3}

What are the solutions to the equation roots x^4-8x^2+16 ?
The solutions to the equation roots x^4-8x^2+16 are x=2,x=-2
Find the zeros of roots x^4-8x^2+16
The zeros of roots x^4-8x^2+16 are x=2,x=-2