What are the solutions to the equation x^1x^2=4+(-sqrt(8/6)) ?

The solutions to the equation x^1x^2=4+(-sqrt(8/6)) are

Find the zeros of x^1x^2=4+(-sqrt(8/6))

The zeros of x^1x^2=4+(-sqrt(8/6)) are

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x^{1} x^{2} = 4 + (- \frac{8}{6})

x = 3 4 - \frac{2}{3}, x = - 3 4 - \frac{2}{3} \frac{1}{2} + 3 4 - \frac{2}{3} \frac{3}{2} i, x = - 3 4 - \frac{2}{3} \frac{1}{2} - 3 4 - \frac{2}{3} \frac{3}{2} i

Solution steps

x^{1} x^{2} = 4 + (- \frac{8}{6})

Simplify

x^{3} = 4 - \frac{2}{3}

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

x = 3 4 - \frac{2}{3}, x = 3 4 - \frac{2}{3} \frac{- 1 + 3 i}{2}, x = 3 4 - \frac{2}{3} \frac{- 1 - 3 i}{2}

Simplify

3 4 - \frac{2}{3} \frac{- 1 + 3 i}{2} : - 3 4 - \frac{2}{3} \frac{1}{2} + 3 4 - \frac{2}{3} \frac{3}{2} i

Simplify

3 4 - \frac{2}{3} \frac{- 1 - 3 i}{2} : - 3 4 - \frac{2}{3} \frac{1}{2} - 3 4 - \frac{2}{3} \frac{3}{2} i

x = 3 4 - \frac{2}{3}, x = - 3 4 - \frac{2}{3} \frac{1}{2} + 3 4 - \frac{2}{3} \frac{3}{2} i, x = - 3 4 - \frac{2}{3} \frac{1}{2} - 3 4 - \frac{2}{3} \frac{3}{2} i

x^{3} + 2 x^{2} - 5 x - 6

x^{3} - 54 x^{2} + 51 x + 106

n^{3} - 6 n^{2} - n + 6 = 0

\frac{x ^{3}}{9} - 1 = 2

x^{4} - 16 x^{2} + 75 = 2 x^{2} - 6

What are the solutions to the equation x^1x^2=4+(-sqrt(8/6)) ?
The solutions to the equation x^1x^2=4+(-sqrt(8/6)) are
Find the zeros of x^1x^2=4+(-sqrt(8/6))
The zeros of x^1x^2=4+(-sqrt(8/6)) are