What are the solutions to the equation factor 2x^4=48x^2 ?

The solutions to the equation factor 2x^4=48x^2 are x=0,x=-2sqrt(6),x=2sqrt(6)

Find the zeros of factor 2x^4=48x^2

The zeros of factor 2x^4=48x^2 are x=0,x=-2sqrt(6),x=2sqrt(6)

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factor

2 x^{4} = 48 x^{2}

x = 0, x = - 26, x = 26

Decimal

x = 0, x = - 4.89897 \dots, x = 4.89897 \dots

Solution steps

2 x^{4} = 48 x^{2}

Move

48 x^{2}

to the left side

2 x^{4} - 48 x^{2} = 0

Factor

2 x^{4} - 48 x^{2} : 2 x^{2} (x + 26) (x - 26)

2 x^{2} (x + 26) (x - 26) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 26 = 0 or x - 26 = 0

Solve

x + 26 = 0 : x = - 26

Solve

x - 26 = 0 : x = 26

The solutions are

x = 0, x = - 26, x = 26

2 x^{4} + 16 x^{3} + 32 x^{2} = 0

x^{4} - x^{2} = 12

3 q (q + 6) 2 (q + 6) = 0

3 x^{5} - 8 x^{4} + 2 x^{3} + 5 x^{2} - 2 x + 1 = 0

2 x^{3} - 6 x + 4 = 0

What are the solutions to the equation factor 2x^4=48x^2 ?
The solutions to the equation factor 2x^4=48x^2 are x=0,x=-2sqrt(6),x=2sqrt(6)
Find the zeros of factor 2x^4=48x^2
The zeros of factor 2x^4=48x^2 are x=0,x=-2sqrt(6),x=2sqrt(6)