What are the solutions to the equation m^3=1 ?

The solutions to the equation m^3=1 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i

Find the zeros of m^3=1

The zeros of m^3=1 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i

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m^{3} = 1

m = 1, m = - \frac{1}{2} + \frac{3}{2} i, m = - \frac{1}{2} - \frac{3}{2} i

Solution steps

m^{3} = 1

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

m = 1, m = \frac{- 1 + 3 i}{2}, m = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

m = 1, m = - \frac{1}{2} + \frac{3}{2} i, m = - \frac{1}{2} - \frac{3}{2} i

r^{3} - 3 r^{2} + 3 r - 1

x^{3} - 3 x^{2} - 40 x = 0

x^{12} - 12 = 36

(x^{2} + 25)^{2} = 0

y, x^{3} + y^{3} = 0

What are the solutions to the equation m^3=1 ?
The solutions to the equation m^3=1 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i
Find the zeros of m^3=1
The zeros of m^3=1 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i