What are the solutions to the equation x^3+8x^2-36x=288 ?

The solutions to the equation x^3+8x^2-36x=288 are x=-8,x=-6,x=6

Find the zeros of x^3+8x^2-36x=288

The zeros of x^3+8x^2-36x=288 are x=-8,x=-6,x=6

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x^{3} + 8 x^{2} - 36 x = 288

x = - 8, x = - 6, x = 6

Solution steps

x^{3} + 8 x^{2} - 36 x = 288

Move

288

to the left side

x^{3} + 8 x^{2} - 36 x - 288 = 0

Factor

x^{3} + 8 x^{2} - 36 x - 288 : (x + 8) (x + 6) (x - 6)

(x + 8) (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 8 = 0 or x + 6 = 0 or x - 6 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = - 8, x = - 6, x = 6

x^{3} - 9 x^{2} + 27 x = 20

4 x^{4} - 14 x^{2} + 12 = 0

x^{3} - 12 x^{2} + 256 = 0

x^{3} + 4 x^{2} - 10

x^{3} - 11 x^{2} + 23 x + 35 = 0

What are the solutions to the equation x^3+8x^2-36x=288 ?
The solutions to the equation x^3+8x^2-36x=288 are x=-8,x=-6,x=6
Find the zeros of x^3+8x^2-36x=288
The zeros of x^3+8x^2-36x=288 are x=-8,x=-6,x=6