What are the solutions to the equation roots x^3-9x^2-4x+36=0 ?

The solutions to the equation roots x^3-9x^2-4x+36=0 are x=9,x=-2,x=2

Find the zeros of roots x^3-9x^2-4x+36=0

The zeros of roots x^3-9x^2-4x+36=0 are x=9,x=-2,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{3} - 9 x^{2} - 4 x + 36 = 0

x = 9, x = - 2, x = 2

Solution steps

x^{3} - 9 x^{2} - 4 x + 36 = 0

Factor

x^{3} - 9 x^{2} - 4 x + 36 : (x - 9) (x + 2) (x - 2)

(x - 9) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 9, x = - 2, x = 2

x^{12} - x^{6} - 30 = 0

240 x^{3} + 360 x^{2} - 1800 x = 0

x^{3} - 2 x^{2} + 9 x - 18

125 = 40 x \frac{1}{2} (10) x^{2}

x^{4} - 8 x^{3} + 26 x^{2} - 40 x + 25 = 0

What are the solutions to the equation roots x^3-9x^2-4x+36=0 ?
The solutions to the equation roots x^3-9x^2-4x+36=0 are x=9,x=-2,x=2
Find the zeros of roots x^3-9x^2-4x+36=0
The zeros of roots x^3-9x^2-4x+36=0 are x=9,x=-2,x=2