What are the solutions to the equation roots x^3+4x^2+x-6 ?

The solutions to the equation roots x^3+4x^2+x-6 are x=1,x=-2,x=-3

Find the zeros of roots x^3+4x^2+x-6

The zeros of roots x^3+4x^2+x-6 are x=1,x=-2,x=-3

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roots

x^{3} + 4 x^{2} + x - 6

x = 1, x = - 2, x = - 3

Solution steps

x^{3} + 4 x^{2} + x - 6

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 4 x^{2} + x - 6 = 0

Factor

x^{3} + 4 x^{2} + x - 6 : (x - 1) (x + 2) (x + 3)

(x - 1) (x + 2) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 1, x = - 2, x = - 3

x^{4} - 3 x^{3} - 13 x^{2} + 9 x + 30 = 0

7 y^{5} - 3 y^{1} = 2 y^{2}

10 x^{3} - 23 x - 1 = 0

a^{2} - 24 a n^{2} x^{2} + 144 n^{4} x^{4}

x^{4} - 4 x^{2} - 2 = 0

What are the solutions to the equation roots x^3+4x^2+x-6 ?
The solutions to the equation roots x^3+4x^2+x-6 are x=1,x=-2,x=-3
Find the zeros of roots x^3+4x^2+x-6
The zeros of roots x^3+4x^2+x-6 are x=1,x=-2,x=-3