What are the solutions to the equation -x^3+8x=0 ?

The solutions to the equation -x^3+8x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)

Find the zeros of -x^3+8x=0

The zeros of -x^3+8x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)

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- x^{3} + 8 x = 0

x = 0, x = - 22, x = 22

Decimal

x = 0, x = - 2.82842 \dots, x = 2.82842 \dots

Solution steps

- x^{3} + 8 x = 0

Factor

- x^{3} + 8 x : - x (x + 22) (x - 22)

- x (x + 22) (x - 22) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 22 = 0 or x - 22 = 0

Solve

x + 22 = 0 : x = - 22

Solve

x - 22 = 0 : x = 22

The solutions are

x = 0, x = - 22, x = 22

x^{5} - x^{2} + 2 x + 3 = 0

- x^{4} + 7 x^{2} - 3 x - 19 = 0

5 x^{3} + 45 x^{2} + 70 x = 0

2 x^{3} + 3 x^{2} - 1

(x + 4)^{3} = 0

What are the solutions to the equation -x^3+8x=0 ?
The solutions to the equation -x^3+8x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)
Find the zeros of -x^3+8x=0
The zeros of -x^3+8x=0 are x=0,x=-2sqrt(2),x=2sqrt(2)