What are the solutions to the equation x^3+4x^2-5x-20=0 ?

The solutions to the equation x^3+4x^2-5x-20=0 are x=-4,x=-sqrt(5),x=sqrt(5)

Find the zeros of x^3+4x^2-5x-20=0

The zeros of x^3+4x^2-5x-20=0 are x=-4,x=-sqrt(5),x=sqrt(5)

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x^{3} + 4 x^{2} - 5 x - 20 = 0

x = - 4, x = - 5, x = 5

Decimal

x = - 4, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

x^{3} + 4 x^{2} - 5 x - 20 = 0

Factor

x^{3} + 4 x^{2} - 5 x - 20 : (x + 4) (x + 5) (x - 5)

(x + 4) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 4, x = - 5, x = 5

x^{3} - 3 x^{2} - 13 x + 15

x = x^{3} - x^{2} - x

x^{3} - 5 x^{2} + 4 x - 20

500 = 0.02 \frac{t ^{4}}{12}

s^{4} + 60 s^{3} + 1400 s^{2} + 2000 s - 130000 = 0

What are the solutions to the equation x^3+4x^2-5x-20=0 ?
The solutions to the equation x^3+4x^2-5x-20=0 are x=-4,x=-sqrt(5),x=sqrt(5)
Find the zeros of x^3+4x^2-5x-20=0
The zeros of x^3+4x^2-5x-20=0 are x=-4,x=-sqrt(5),x=sqrt(5)