What are the solutions to the equation u^3+2u^2-8u=0 ?

The solutions to the equation u^3+2u^2-8u=0 are u=0,u=2,u=-4

Find the zeros of u^3+2u^2-8u=0

The zeros of u^3+2u^2-8u=0 are u=0,u=2,u=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{3} + 2 u^{2} - 8 u = 0

u = 0, u = 2, u = - 4

Solution steps

u^{3} + 2 u^{2} - 8 u = 0

Factor

u^{3} + 2 u^{2} - 8 u : u (u - 2) (u + 4)

u (u - 2) (u + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u = 0 or u - 2 = 0 or u + 4 = 0

Solve

u - 2 = 0 : u = 2

Solve

u + 4 = 0 : u = - 4

The solutions are

u = 0, u = 2, u = - 4

y, y^{2} = 5 x^{4} - x^{2}

3 x^{3} + x^{2} - 3 x - 1 = 0

4 x^{4} + 19 x^{2} - 5 = 0

x^{3} + x^{2} + x + 1 = 0

x^{4} - x^{3} - 30 x^{2}

What are the solutions to the equation u^3+2u^2-8u=0 ?
The solutions to the equation u^3+2u^2-8u=0 are u=0,u=2,u=-4
Find the zeros of u^3+2u^2-8u=0
The zeros of u^3+2u^2-8u=0 are u=0,u=2,u=-4